669A - Little Artem and Presents - CodeForces Solution

math *800

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Python Code: 

n = int(input())

print(n//3*2 + (n%3>0))

C++ Code: 

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int main(){
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
//    freopen("input.txt","r", stdin);
    int n;cin>>n;
    int ans=1;
    if (n>2){
        ans=2*(n/3) + (n%3>0);
    }
    cout << ans << endl;

}


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