n = int(input())
l = 0
for i in range(n):
st = input().split()
name, before, after = st[0], int(st[1]), int(st[2])
if 2400 <= before < after: print('YES');l=1;break
if l == 0:print('NO')#include <bits/stdc++.h>
using namespace std;
int main()
{
int n,b,a;
string s;
cin>>n;
while(n--)
{
cin>>s>>b>>a;
if(b>=2400 && a>b)
{
cout<<"YES";
return 0;
}
}
cout<<"NO";
return 0;
}
Zoos | Build a graph |
Almost correct bracket sequence | Count of integers |
Differences of the permutations | Doctor's Secret |
Back to School | I am Easy |
Teddy and Tweety | Partitioning binary strings |
Special sets | Smallest chosen word |
Going to office | Color the boxes |
Missing numbers | Maximum sum |
13 Reasons Why | Friend's Relationship |
Health of a person | Divisibility |
A. Movement | Numbers in a matrix |
Sequences | Split houses |
Divisible | Three primes |
Coprimes | Cost of balloons |
One String No Trouble | Help Jarvis! |