import sys
input = lambda: sys.stdin.readline().strip()
s = input()
def bd_pq_swap(s):
return ''.join(
'p' if c == 'q' else
'q' if c == 'p' else
'b' if c == 'd' else
'd' if c == 'b' else
c
for c in s
)
mirrored = 'AbdHIMOopqTUVvWwXxY'
print('TAK' if s == ''.join(reversed(bd_pq_swap(s))) and all(c in mirrored for c in s) else 'NIE')
// Problem: B. s-palindrome
// Contest: Codeforces - Educational Codeforces Round 14
// URL: https://codeforces.com/contest/691/problem/B
// Memory Limit: 256 MB
// Time Limit: 1000 ms
//
// Powered by CP Editor (https://cpeditor.org)
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e5+5;
bool check(char c){
string s="AHIMOoTUVvWwXxY";
for(int i=0;i<s.size();i++){
if(c==s[i]) return true;
}
return false;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0),cout.tie(0);
string a;
cin>>a;
bool flag=false;
for(int i=0;i<a.size();i++){
if(a[i]==a[a.size()-i-1]&&check(a[i])){
flag=true;
}
else if((a[i]=='b'&&a[a.size()-i-1]=='d')||(a[i]=='p'&&a[a.size()-i-1]=='q')||(a[i]=='d'&&a[a.size()-i-1]=='b')||(a[i]=='q'&&a[a.size()-i-1]=='p')){
flag=true;
}
else{
cout<<"NIE\n";
return 0;
}
}
//cout<<a[ans]<<' '<<a[a.size()-ans-1]<<"\n";
//cout<<ans<<" ";
cout<<"TAK\n";
return 0;
}
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