6C - Alice Bob and Chocolate - CodeForces Solution


greedy two pointers *1200

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Python Code:

n = int(input())
s = list(map(int, input().split()))
l, r = 0, n-1
a, b = 0, 0
for i in range(n):
    if a <= b:
        a += s[l]
        l += 1
    elif b < a:
        b += s[r]
        r -= 1
print(l, n - r - 1)


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