716C - Plus and Square Root - CodeForces Solution


constructive algorithms math number theory *1600

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Python Code:

n = int(input())

if n == 3:
    print(14)
    print(16)
    print(46)
    exit(0)
if n == 2:
    print(999999999999999998)
    print(44500000000)
    exit(0)
for i in range(1, n+1):
    if i == 1:
        print(2)
    else:
        print(i*(i+1)*(i+1)-(i-1))


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