from math import ceil, remainder
def capture_numbers():
line = input()
return [int(number) for number in line.split(' ')]
elements, max, percentage = capture_numbers()
step = 100 / elements
values = [0 for index in range(elements)]
fulls = int(percentage / step)
remaining = percentage - (fulls * step)
pwm = int(remaining * max / step)
for index in range(fulls):
values[index] = max
if remaining != 0:
values[fulls] = pwm
print(' '.join([str(value) for value in values]))#include<iostream>
#include<vector>
#include<utility>
#include<map>
#include<unordered_map>
#include<algorithm>
#include<cmath>
#include<stack>
#include<iterator>
#include<deque>
#include<queue>
#include<unordered_set>
#include<set>
using namespace std;
using ll = long long;
#define rep(i, a, b) for(ll i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
#define F first
#define S second
#define MANEX main
using pii = pair<ll, ll>;
using vi = vector<ll>;
using vp = vector<pii>;
const ll INF = 1e18 + 10;
const int MAX = 1e5 + 10;
void solve() {
int n, k, t;
scanf("%d%d%d", &n, &k, &t);
int canHave = (n * k * t) / 100;
for(int i = 0; i < n; i++) {
if(canHave > k) printf("%d ", k);
else if(canHave > 0) printf("%d ", canHave);
else printf("%d ", 0);
canHave -= k;
}
printf("\n");
}
int MANEX() {
solve();
}
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