801A - Vicious Keyboard - CodeForces Solution

brute force *1100

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Python Code: 

s = input()

ans = 0 

for i in range(len(s)-1):
    if s[i] == 'V' and s[i+1] == 'K':
        ans += 1

if s[:2] == 'KK' or s[-2:] == 'VV' or s.find('VVV') != -1 or s.find('KKK') != -1:
    ans += 1

print(ans)


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