873A - Chores - CodeForces Solution


implementation *800

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Python Code:

n , k , x = map(int , input().split())
l = input().split()
for i in range(len(l)):
    l[i]=int(l[i])
count = 0
for i in range(len(l)-k):
    count+=l[i]
print(count+(k*x))

C++ Code:

#include <stdio.h>
#include <string.h>
#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
int main()
{
    int n,k,x;
    int a;
    scanf("%d%d%d",&n,&k,&x);
    int sum=0;
    for(int i=0;i<n-k;i++)
    {
        scanf("%d",&a);
        sum+=a;
    }
    for(int i=0;i<k;i++)
    {
        scanf("%d",&a);
        sum+=x;
    }
    cout << sum << endl;
    return 0;
}


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