Number of triangles - HackerEarth Solution


Math Array

Python Code:

t = int(input())

for i in range(t):
    n ,b1, b2 = list(map(int, input().split()))
    b1-=1
    b2-=1

    count = 0



    for j in range(n):


        if j==b1 or j== b2:
            continue

        elif (j+1)%n == b1 or (j+1)%n == b2:
            continue


        else:
            x = ((j-1)%n +n)%n

            if x==b1 or x ==b2:
                x = 0
            else:
                x=1


            count+= n - 4 - x

    print(count)


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