class Solution:
def commonChars(self, words: List[str]) -> List[str]:
actual_dict = {}
for i in range(len(words[0])):
if words[0][i] in actual_dict:
actual_dict[words[0][i]]+=1
else:
actual_dict[words[0][i]]=1
for i in range(1, len(words), 1):
another = {}
for j in range(len(words[i])):
if words[i][j] in another:
another[words[i][j]] +=1
else:
another[words[i][j]] = 1
for j in actual_dict:
if j in another:
if another[j] <= actual_dict[j]:
actual_dict[j] = another[j]
else:
actual_dict[j] = -1
ans = []
for i in actual_dict:
if actual_dict[i] == -1:
continue
else:
ans+= [i] * actual_dict[i]
return ans
729D - Sea Battle | 788A - Functions again |
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1726B - Mainak and Interesting Sequence | 1726D - Edge Split |
1726C - Jatayu's Balanced Bracket Sequence | 1726A - Mainak and Array |
1613C - Poisoned Dagger | 475B - Strongly Connected City |
652B - z-sort | 124B - Permutations |
1496C - Diamond Miner | 680B - Bear and Finding Criminals |
1036E - Covered Points | 1015D - Walking Between Houses |
155B - Combination | 1531A - Зингер | color |
1678A - Tokitsukaze and All Zero Sequence | 896A - Nephren gives a riddle |
761A - Dasha and Stairs | 1728B - Best Permutation |
1728A - Colored Balls Revisited | 276B - Little Girl and Game |
1181A - Chunga-Changa | 1728C - Digital Logarithm |
1728D - Letter Picking | 792B - Counting-out Rhyme |