1365. How Many Numbers Are Smaller Than the Current Number - LeetCode Solution

class Solution:
    def smallerNumbersThanCurrent(self, nums: List[int]) -> List[int]:
        d = []
        for i in nums:
            count = 0
            for j in nums:
                if(i>j):
                    count+=1
                else:
                    continue
            d.append(count)


        return d