1374. Generate a String With Characters That Have Odd Counts - LeetCode Solution


String

Python Code:

class Solution:
    def generateTheString(self, n: int) -> str:
        if n%2==0:
            return "a" * (n-1) + "b"
        else:
            return "a" * n


Comments

Submit
0 Comments
More Questions

520A - Pangram
124A - The number of positions
1041A - Heist
901A - Hashing Trees
1283A - Minutes Before the New Year
1654D - Potion Brewing Class
1107B - Digital root
25A - IQ test
785A - Anton and Polyhedrons
1542B - Plus and Multiply
306A - Candies
1651C - Fault-tolerant Network
870A - Search for Pretty Integers
1174A - Ehab Fails to Be Thanos
1169A - Circle Metro
780C - Andryusha and Colored Balloons
1153A - Serval and Bus
1487C - Minimum Ties
1136A - Nastya Is Reading a Book
1353B - Two Arrays And Swaps
1490E - Accidental Victory
1335A - Candies and Two Sisters
96B - Lucky Numbers (easy)
1151B - Dima and a Bad XOR
1435B - A New Technique
1633A - Div 7
268A - Games
1062B - Math
1294C - Product of Three Numbers
749A - Bachgold Problem