class Solution:
def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
count = 0
for i in range(len(words)):
flag = 0
for j in range(len(words[i])):
if words[i][j] in allowed:
flag = 0
else:
flag = 1
break
if flag ==0:
count+=1
return count
630I - Parking Lot | 160B - Unlucky Ticket |
371B - Fox Dividing Cheese | 584B - Kolya and Tanya |
137B - Permutation | 550C - Divisibility by Eight |
5A - Chat Servers Outgoing Traffic | 615A - Bulbs |
5B - Center Alignment | 549A - Face Detection |
535B - Tavas and SaDDas | 722C - Destroying Array |
366A - Dima and Guards | 716B - Complete the Word |
1461C - Random Events | 1627A - Not Shading |
141B - Hopscotch | 47B - Coins |
1466C - Canine poetry | 74A - Room Leader |
1333D - Challenges in school №41 | 1475B - New Year's Number |
461A - Appleman and Toastman | 320B - Ping-Pong (Easy Version) |
948A - Protect Sheep | 387A - George and Sleep |
53A - Autocomplete | 1729G - Cut Substrings |
805B - 3-palindrome | 805C - Find Amir |