class Solution:
def minimumCost(self, cost: List[int]) -> int:
cost.sort(reverse=True)
res, i, N = 0, 0, len(cost)
while i < N:
res += sum(cost[i : i + 2])
i += 3
return res
832A - Sasha and Sticks | 292B - Network Topology |
1339A - Filling Diamonds | 910A - The Way to Home |
617A - Elephant | 48A - Rock-paper-scissors |
294A - Shaass and Oskols | 1213A - Chips Moving |
490A - Team Olympiad | 233A - Perfect Permutation |
1360A - Minimal Square | 467A - George and Accommodation |
893C - Rumor | 227B - Effective Approach |
1534B - Histogram Ugliness | 1611B - Team Composition Programmers and Mathematicians |
110A - Nearly Lucky Number | 1220B - Multiplication Table |
1644A - Doors and Keys | 1644B - Anti-Fibonacci Permutation |
1610A - Anti Light's Cell Guessing | 349B - Color the Fence |
144A - Arrival of the General | 1106A - Lunar New Year and Cross Counting |
58A - Chat room | 230A - Dragons |
200B - Drinks | 13A - Numbers |
129A - Cookies | 1367B - Even Array |