221. Maximal Square - LeetCode Solution


Array Dynamic Programming

Python Code:

class Solution(object):
    def maximalSquare(self, matrix):
        dp, ans = [[0] * len(matrix[0]) for row in matrix], 0
        for i in range(len(matrix)):
            for j in range(len(matrix[0])):
                if matrix[i][j] == '1':
                    dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]) + 1
                    ans = max(ans, dp[i][j] ** 2)
        return ans


Comments

Submit
0 Comments
More Questions

1157E - Minimum Array
1661D - Progressions Covering
262A - Roma and Lucky Numbers
1634B - Fortune Telling
1358A - Park Lighting
253C - Text Editor
365B - The Fibonacci Segment
75A - Life Without Zeros
1519A - Red and Blue Beans
466A - Cheap Travel
659E - New Reform
1385B - Restore the Permutation by Merger
706A - Beru-taxi
686A - Free Ice Cream
1358D - The Best Vacation
1620B - Triangles on a Rectangle
999C - Alphabetic Removals
1634C - OKEA
1368C - Even Picture
1505F - Math
1473A - Replacing Elements
959A - Mahmoud and Ehab and the even-odd game
78B - Easter Eggs
1455B - Jumps
1225C - p-binary
1525D - Armchairs
1257A - Two Rival Students
1415A - Prison Break
1271A - Suits
259B - Little Elephant and Magic Square