class Solution(object):
def maximalSquare(self, matrix):
dp, ans = [[0] * len(matrix[0]) for row in matrix], 0
for i in range(len(matrix)):
for j in range(len(matrix[0])):
if matrix[i][j] == '1':
dp[i][j] = min(dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]) + 1
ans = max(ans, dp[i][j] ** 2)
return ans
1157E - Minimum Array | 1661D - Progressions Covering |
262A - Roma and Lucky Numbers | 1634B - Fortune Telling |
1358A - Park Lighting | 253C - Text Editor |
365B - The Fibonacci Segment | 75A - Life Without Zeros |
1519A - Red and Blue Beans | 466A - Cheap Travel |
659E - New Reform | 1385B - Restore the Permutation by Merger |
706A - Beru-taxi | 686A - Free Ice Cream |
1358D - The Best Vacation | 1620B - Triangles on a Rectangle |
999C - Alphabetic Removals | 1634C - OKEA |
1368C - Even Picture | 1505F - Math |
1473A - Replacing Elements | 959A - Mahmoud and Ehab and the even-odd game |
78B - Easter Eggs | 1455B - Jumps |
1225C - p-binary | 1525D - Armchairs |
1257A - Two Rival Students | 1415A - Prison Break |
1271A - Suits | 259B - Little Elephant and Magic Square |