229. Majority Element II - LeetCode Solution


Array

Python Code:

class Solution:
    def majorityElement(self, nums: List[int]) -> List[int]:
        
        c = {}
        
        d = []
        
        for i in nums:
            if i in c:
                c[i] +=1
            else:
                c[i] = 1
                
                
        for i in c:
            if c[i] > len(nums)/3:
                d.append(i)
        
        return d


Comments

Submit
0 Comments
More Questions

1566B - MIN-MEX Cut
678C - Joty and Chocolate
1352E - Special Elements
1520E - Arranging The Sheep
1157E - Minimum Array
1661D - Progressions Covering
262A - Roma and Lucky Numbers
1634B - Fortune Telling
1358A - Park Lighting
253C - Text Editor
365B - The Fibonacci Segment
75A - Life Without Zeros
1519A - Red and Blue Beans
466A - Cheap Travel
659E - New Reform
1385B - Restore the Permutation by Merger
706A - Beru-taxi
686A - Free Ice Cream
1358D - The Best Vacation
1620B - Triangles on a Rectangle
999C - Alphabetic Removals
1634C - OKEA
1368C - Even Picture
1505F - Math
1473A - Replacing Elements
959A - Mahmoud and Ehab and the even-odd game
78B - Easter Eggs
1455B - Jumps
1225C - p-binary
1525D - Armchairs