class Solution:
def findRightInterval(self, intervals: List[List[int]]) -> List[int]:
s = sorted([(it[0], i) for i, it in enumerate(intervals)])
ans = []
for it in intervals:
i = bisect.bisect_left(s, (it[1], -1))
ans.append(s[i][1] if i < len(s) else -1)
return ans
519A - A and B and Chess | 725B - Food on the Plane |
154B - Colliders | 127B - Canvas Frames |
107B - Basketball Team | 245A - System Administrator |
698A - Vacations | 1216B - Shooting |
368B - Sereja and Suffixes | 1665C - Tree Infection |
1665D - GCD Guess | 29A - Spit Problem |
1097B - Petr and a Combination Lock | 92A - Chips |
1665B - Array Cloning Technique | 1665A - GCD vs LCM |
118D - Caesar's Legions | 1598A - Computer Game |
1605A - AM Deviation | 1461A - String Generation |
1585B - Array Eversion | 1661C - Water the Trees |
1459A - Red-Blue Shuffle | 1661B - Getting Zero |
1661A - Array Balancing | 1649B - Game of Ball Passing |
572A - Arrays | 1455A - Strange Functions |
1566B - MIN-MEX Cut | 678C - Joty and Chocolate |