class Solution:
def atMostNGivenDigitSet(self, D: List[str], N: int) -> int:
S = str(N)
K = len(S)
dp = [0] * K + [1]
for i in range(K-1, -1, -1):
# Compute dp[i]
for d in D:
if d < S[i]:
dp[i] += len(D) ** (K-i-1)
elif d == S[i]:
dp[i] += dp[i+1]
return dp[0] + sum(len(D) ** i for i in range(1, K))
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268A - Games | 1062B - Math |
1294C - Product of Three Numbers | 749A - Bachgold Problem |
1486B - Eastern Exhibition | 1363A - Odd Selection |