php get url parameter

109

$parts = parse_url($url);
parse_str($parts['query'], $query);
echo $query['email'];
phpCopy<?php 
echo $_GET['email'] . $_GET['name']
?> 
phpCopy<?php 
$url = "https://testurl.com/test/[email protected]&name=sarah";
$components = parse_url($url);
parse_str($components['query'], $results);
print_r($results); 
?> 
<?php
if (isset($_GET['link'])) {
    echo $_GET['link'];
} else {
    // Fallback behaviour goes here
}
phpCopy<?php 
$url = "https://testurl.com/test/[email protected]&name=sarah";
$components = parse_url($url);
parse_str($components['query'], $results);
echo($results['email']); 
?> 
phpCopy<?php 
$url = "https://testurl.com/test/[email protected]&name=sarah";
$components = parse_url($url, PHP_URL_QUERY);
//$component parameter is PHP_URL_QUERY
parse_str($components, $results);
print_r($results); 
?> 

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