get current file name python

import os
os.path.dirname(os.path.abspath(__file__))

# Option 1: Works for Python 3.4 +
from pathlib import Path
Path(__file__).name		# ScriptName.py
Path(__file__).stem		# ScriptName

# Option 2: use `os` library 
import os
os.path.basename(__file__)							# ScriptName.py
os.path.splitext(os.path.basename(__file__))[0]		# ScriptName

import os
os.path.basename(__file__)

Use __file__. If you want to omit the directory part (which might be present), you can use os.path.basename(__file__)