pandas select row by index

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how to get a row from a dataframe in python -

df.iloc[[index]]

dataframe get row by name -

row_data = df.loc[ 'a' , : ]

isolate row based on index pandas -

dfObj.iloc[: , [0, 2]]

select rows from dataframe pandas -

from pandas import DataFrame

boxes = {'Color': ['Green','Green','Green','Blue','Blue','Red','Red','Red'],
         'Shape': ['Rectangle','Rectangle','Square','Rectangle','Square','Square','Square','Rectangle'],
         'Price': [10,15,5,5,10,15,15,5]
        }

df = DataFrame(boxes, columns= ['Color','Shape','Price'])

select_color = df.loc[df['Color'] == 'Green']
print (select_color)

pandas select a row -

#select the first row 
df.iloc[1]
#select the first row and return the value in column ['Biologie']
candidate_df.iloc[1]['Biologie']

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